Grep. How do I escape the number 0 in a replacement string if \0
is already reserved?

I need to immediately follow \1 with a literal 0 and don't know
how to do that.

Thanks.

Ken

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use \010

ref p.183 of bbedit user manual ( http://pine.barebones.com/manual/BBEdit_9_User_Manual.pdf
) under "In Replacement Patterns":

--
You may use a leading zero; for example, if in your replacement
pattern you want the rst backreference followed by a literal
“1”, you can use “\011”. (If you use “\11”, you will get
the 11th backreference, even if it is empty.)
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On Mar 11, 2010, at 2:14 AM, klanxner@[Protected] wrote:

> Grep. How do I escape the number 0 in a replacement string if \0 is
> already reserved?
>
> I need to immediately follow \1 with a literal 0 and don't know how
> to do that.
>
> Thanks.
>
> Ken
>
> --
> Simple Lives Web Design
> http://simplelives.com
>
> --
> You received this message because you are subscribed to the "BBEdit
> Talk" discussion group on Google Groups.
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Much thanks.

Ken

bbyllesby@[Protected] (Brian Byllesby) wrote on 3/11/10 3:20 AM

>use \010
>
>ref p.183 of bbedit user manual (
>http://pine.barebones.com/manual/BBEdit_9_User_Manual.pdf )
>under "In Replacement Patterns":
>
>--
>You may use a leading zero; for example, if in your replacement
>pattern you want the rst backreference followed by a literal
>“1”, you can use “\011”. (If you use “\11”, you
>will get the 11th backreference, even if it is empty.)
>--

>On Mar 11, 2010, at 2:14 AM, klanxner@[Protected] wrote:
>
>>Grep. How do I escape the number 0 in a replacement string if
>>\0 is already reserved?

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